martes, 24 de mayo de 2011

PROBLEMA:

 AREA DEL TERRENO


A= BXH


 A= 4mX16m
A= 64m2





PERIMETRO

P=L+L+L+L+L


P=4m+16m+4m+16m


P=40m
                                                            

C (9, 7.5)           R= 1.90


(x-h)+ (y-k)= r2



(x-9)2 +(y-7.5)= (1.90)2


(x-9)2+(y-7.5)2= 3.61 ........................................... FORMA ORDINARIA




X2-18X+81+Y2 -15Y+56.2= 3.61

X2-18X+Y2-15Y+81+56.2-3.61= 0

X2-18X+Y2-15Y+133.5= 0 ...................................... ECUACION GENERAL


DERIVADA DEL TERRENO:

Y= X2-18X+Y2-15Y+133.5
                                                                                     

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